Question

What is the electric field outside a solid non-conducting uniformly charged sphere, where \[r > R\]?

पर्याय

• \[E = \frac{Qr}{4\pi\varepsilon_0 R^3}\]

• \[E = \frac{Q}{4\pi\varepsilon_0 R^2}\]

• \[E = 0\]

• \[E = \frac{Q}{4\pi\varepsilon_0 r^2}\]

Answer 1

Outside the sphere, a concentric Gaussian surface encloses the total charge \[Q\]. The resulting field is \[E = Q/(4\pi\varepsilon_0 r^2)\].