Question

What is the electric field just outside a single conducting plate with surface charge density \[\sigma\]?

पर्याय

• \[E = \frac{\sigma A}{\varepsilon_0}\]

• \[E = \frac{\sigma}{\varepsilon_0}\]

• \[E = \frac{2\sigma}{\varepsilon_0}\]

• \[E = \frac{\sigma}{2\varepsilon_0}\]

Answer 1

Only one face of the pillbox carries flux because the field is zero inside the conductor. Gauss's Law gives \[EA = \sigma A/\varepsilon_0\], hence \[E = \sigma/\varepsilon_0\].