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प्रश्न
What equation is obtained after multiplying through by \[\sqrt{1-x^2}\] in the derivation for \[y=\sin^{-1}x\]?
पर्याय
\[(1-x^2)\frac{dy}{dx}-x\frac{d^2y}{dx^2}=0\]
\[\frac{d^2y}{dx^2}-x\frac{dy}{dx}=0\]
\[(1-x^2)\frac{d^2y}{dx^2}-x\frac{dy}{dx}=0\]
\[(1-x^2)\frac{d^2y}{dx^2}+x\frac{dy}{dx}=0\]
MCQ
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उत्तर
Multiplication by \[\sqrt{1-x^2}\] changes the first coefficient to \[1-x^2\]. The remaining term becomes \[-x\frac{dy}{dx}\], giving the stated differential equation.
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