Question

What do you understand by the normality of a solution?

Answer 1

The number of gram equivalents of the solute dissolved per litre of a solution at a particular temperature is called the normality of the solution.

Normality of a solution is represented by N.

Normality = `"Number of gram equivalents of solute"/"Volume of solution in litres"`    ...(1)

If, w = mass of the solute in grams,

v = volume of solution in cm³, 

E = equivalent mass of the solute, and

N = normality of the solution (in g eq L⁻¹),

we have,

number of gram equivalents of solute = `w/E`

Volume of solution in litres = `v/1000`

Substituting the values in equation (1), we have

`N = (w//E)/(v//1000)`

= `(w xx 1000)/(E xx v)`

or

`w = (N xx E xx v)/1000`