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प्रश्न
What differential equation follows when \[v=v_m\sin\omega t\] is applied across a pure inductor?
पर्याय
\[\frac{di}{dt}=\frac{v_m}{L}\sin\omega t\]
\[\frac{di}{dt}=\frac{v_m}{L}\cos\omega t\]
\[\frac{di}{dt}=v_mL\sin\omega t\]
\[\frac{di}{dt}=\frac{L}{v_m}\sin\omega t\]
MCQ
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उत्तर
Substitute the applied voltage into \[L\frac{di}{dt}=v\]. Dividing by \[L\] gives \[\frac{di}{dt}=\frac{v_m}{L}\sin\omega t\].
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