Question

What de Broglie wavelength is obtained for the electron?

पर्याय

• \[0.135\ \mathrm{nm}\]

• \[5.4\times10^{6}\ \mathrm{nm}\]

• \[1.47\times10^{-34}\ \mathrm{m}\]

• \[30.0\ \mathrm{m}\]

Answer 1

Using the electron’s mass and speed in \[\lambda=\frac{h}{mv}\] gives \[0.135\ \mathrm{nm}\]. This is much larger than the wavelength calculated for the ball.