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प्रश्न
Weight of 60 eggs were recorded as given below:
| Weight (in grams) | 75 – 79 | 80 – 84 | 85 – 89 | 90 – 94 | 95 – 99 | 100 - 104 | 105 - 109 |
| No. of eggs | 4 | 9 | 13 | 17 | 12 | 3 | 2 |
Calculate their mean weight to the nearest gram.
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उत्तर
Let us choose a = 92, h = 5, then` d_i = x_i – 92 and u_i = (x_i− 92)/5`
Using step-deviation method, the given data is shown as follows:
| Weight (in grams) |
Number of eggs `(f_i)` |
Class mark `(x_i)` |
`d_i = x_i` – 92 | `u_i =( x_i−92)/ 5` |
`(f_i u_i)` |
| 74.5 – 79.5 | 4 | 77 | -15 | -3 | -12 |
| 79.5 – 84.5 | 9 | 82 | -10 | -2 | -18 |
| 84.5 – 89.5 | 13 | 87 | -5 | -1 | -13 |
| 89.5 – 94.5 | 17 | 92 | 0 | 0 | 0 |
| 94.5 – 99.5 | 12 | 97 | 5 | 1 | 12 |
| 99.5 – 104.5 | 3 | 102 | 10 | 2 | 6 |
| 104.5 – 109.5 | 2 | 107 | 15 | 3 | 6 |
| Total | `Ʃ f_i` = 60 | `Ʃ f_i u_i` = -19 |
The mean of the given data is given by,
x = a + `((Ʃ_i f_i u_i)/(Ʃ _i f_i)) xxh`
=`92+((-19)/(60))xx5`
= 92 – 1.58
=90.42
≈ 90
Thus, the mean weight to the nearest gram is 90 g.
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