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प्रश्न
Verify that sin 2A = `(2 tan A)/(1 + tan^2A)`, for A = 30°.
बेरीज
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उत्तर
sin 2A = `(2 tan A)/(1 + tan^2A)`
For A = 30°
L.H.S. = sin 2A
= sin 2(30°)
= sin 60°
= `sqrt(3)/2`
R.H.S. = `(2 tan A)/(1 + tan^2A)`
= `(2 tan 30°)/(1 + tan^2 30°)`
= `(2(1/sqrt(3)))/(1 + (1/sqrt(3))^2`
= `(2/sqrt(3))/(1 + 1/3)`
= `(2/sqrt(3))/(4/3)`
= `(2 xx 3)/(4sqrt(3))`
= `sqrt(3)/2`
L.H.S. = R.H.S.
Hence proved.
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