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प्रश्न
Verify Rolle’s theorem for the function, f(x) = –1 + cos x in the interval [0, 2π]
बेरीज
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उत्तर
For a function f(x)
Continuous in [a, b]
Differentiate in (a, b)
f(a) = f(b)
Then there exist atleast one value of c for which f(x) = 0.
f(0) = –1 + cos (0) = 0
f(2π) = –1 + cos (2π) = 0
f’(x) = – sin x
f’(x) – sin x = 0
x = π
This proves rolle’s theorem.
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