Question

Using VSEPR theory, predict the probable structure of \[\ce{ICl^-_4}\].

Answer 1

1. The central atom, iodine (I), has 7 valence electrons.
2. Attach 4 chlorine atoms (Cl) and 1 extra electron for negative charge. A total of 12 valence electrons around I.
3. Electron pairs 4 bonding pairs and 2 lone pairs on iodine.
4. Shape by VSEPR octahedral electron geometry.
5. Lone pairs occupy opposite positions.
6. Molecular shape: Square planar for (\[\ce{ICl^-_4}\]), like (XeF₄).
7. Bond angles are approximately 90°.

Thus, (\[\ce{ICl^-_4}\]) has a square planar structure according to VSEPR theory.