Advertisements
Advertisements
प्रश्न
Using the function f and g given below, find fog and gof. Check whether fog = gof
f(x) = `(x + 6)/3`, g(x) = 3 – x
Advertisements
उत्तर
f(x) = `(x + 6)/3`, g(x) = 3 – x
fog = f[g(x)]
= f(3 – x)
= `(3 - x + 6)/3`
= `(9 - x)/3`
gof = g[f(x)]
= `"g"((x + 6)/3)`
= `3 - ((x + 6))/3`
= `(9 - x - 6)/3`
= `(3 - x)/3`
fog ≠ gof
APPEARS IN
संबंधित प्रश्न
Using the function f and g given below, find fog and gof. Check whether fog = gof
f(x) = 3 + x, g(x) = x – 4
Find the value of k, such that fog = gof
f(x) = 2x – k, g(x) = 4x + 5
If f(x) = 2x – 1, g(x) = `(x + 1)/(2)`, show that fog = gof = x
Find k, if f(k) = 2k – 1 and fof(k) = 5
If f(x) = x2 – 1. Find fofof
If f : R → R and g : R → R are defined by f(x) = x5 and g(x) = x4 then check if f, g are one-one and fog is one-one?
Consider the function f(x), g(x), h(x) as given below. Show that (fog)oh = fo(goh)
f(x) = x – 1, g(x) = 3x + 1 and h(x) = x2
Consider the function f(x), g(x), h(x) as given below. Show that (fog)oh = fo(goh)
f(x) = x – 4, g(x) = x2 and h(x) = 3x – 5
Multiple choice question :
If f(x) = 2x2 and g(x) = `1/(3x)`, then fog is
Multiple choice question :
Let f and g be two function given by f = {(0, 1), (2, 0), (3, – 4), (4, 2), (5, 7)} g = {(0, 2), (1, 0), (2, 4), (– 4, 2), (7, 0) then the range of fog is
