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प्रश्न
Using properties of the definite integral, calculate the value of:
`∫_0^(x/2) sin^2 x/(1 + sinx cos x) dx`
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उत्तर
Let
I = `∫_0^(x/2) sin^2 x/(1 + sinx cos x) dx` ...[1]
`∫_0^a f(x)dx = ∫_0^a f(a − x)dx`
Replacing x with (`π/2` − x)
I = `∫_0 ^(π/2) cos^2 x/(1 + cos x sin x) dx` ...[2]
2I = `∫_0 ^(π/2) (sin^2 x + cos^2 x)/(1 + sin x cos x) dx` ...[Adding (1) and (2)]
= `∫_0 ^(π/2) 1/(1 + sin x cos x) dx`
2I = `∫_0 ^(π/2) sec^2 x/(sec^2 x + tan x) dx = ∫_0 ^(π/2) sec^2 x/(1 + tan^2 x + tan x) dx`
Let tan x = t, then sec2 x dx = dt
limits change from [0, π/2] to [0, ∞].
2I = `∫_0^∞ dt/(t^2 + t +1) = ∫_0^∞ dt/((t + 1/2)^2 + (sqrt3/2)^2)`
`∫ dx/(x^2 + a^2) = 1/a tan^(−1) (x/a)`
2I `[2/sqrt3 tan^(−1)] ((t + 1/2)/(sqrt3/2))]_0^∞`
2I = `2/sqrt3[tan^(−1)(∞) − tan^(−1)(1/sqrt3)]`
2I = `2/sqrt3[π/2 − π/6]`
2I = `2/sqrt3 × π/3`
2I = `(2π)/(3sqrt3)`
I = `π/(3sqrt3)`
