Question

Using Kirchhoff’s laws of electrical networks, calculate the current I₃.

Answer 1

I₃ = I₃ + I₂

Applying KVL to the loop ABCDEFA,

2 I₁ + 8 (I₁ + I₂) + 1 I₁ = 33

2 I₁ + 8 I₁ + 8 I₂ + 1 I₁ = 33

11 I₁ + 8 I₂ = 33

Applying KVL to the loop BCDEB,

6 I₂ + 8 (I₁ + I₂) + 2 I₂ = 26

6 I₂ ​+ 8 I₁ ​+ 8 I₁ ​+ 2 I₂ ​= 24

8 I₁ + 16 I₂ = 24

On solving, we get

I₁ = 3A, I₂ = 0

∴ I₃ = I₁ + I₂ = 3A