Advertisements
Advertisements
प्रश्न
Using the factor theorem, show that (x - 2) is a factor of `x^3 + x^2 -4x -4 .`
Hence factorise the polynomial completely.
Advertisements
उत्तर
`f(x) = x^3 + x^2 - 4x - 4`
Let x - 2 = 0, then x = 2
`therefore f(2) = (2)^3 +(2)^2 - 4 (2)-4`
f (2) = 8 + 4 - 8 - 4
f (2) = 0
∴ x - 2 is a factor of f (x)

Now dividing x3 + x2 - 4x - 4 by x - 2, we get
`=x^3 +x^2 - 4x +4 = (x-2)(x^2 + 3x + 2)`
= (x - 2) (x + 2) (x + 1 )
APPEARS IN
संबंधित प्रश्न
When divided by x – 3 the polynomials x3 – px2 + x + 6 and 2x3 – x2 – (p + 3) x – 6 leave the same remainder. Find the value of ‘p’.
Using the Remainder Theorem, factorise each of the following completely.
3x3 + 2x2 – 23x – 30
The expression 4x3 – bx2 + x – c leaves remainders 0 and 30 when divided by x + 1 and 2x – 3 respectively. Calculate the values of b and c. Hence, factorise the expression completely.
Find the number that must be subtracted from the polynomial 3y3 + y2 – 22y + 15, so that the resulting polynomial is completely divisible by y + 3.
Using remainder Theorem, factorise:
2x3 + 7x2 − 8x – 28 Completely
Find the value of a and b so that the polynomial x3 - ax2 - 13x + b has (x - 1) (x + 3) as factor.
If the polynomials ax3 + 4x2 + 3x - 4 and x3 - 4x + a leave the same remainder when divided by (x - 3), find the value of a.
In the following two polynomials. Find the value of ‘a’ if x + a is a factor of each of the two:
x3 + ax2 − 2x + a + 4
In the following two polynomials, find the value of ‘a’ if x – a is a factor of each of the two:
x6 - ax5 + x4 - ax3 + 3a + 2
Prove that (5x + 4) is a factor of 5x3 + 4x2 – 5x – 4. Hence factorize the given polynomial completely.
