Advertisements
Advertisements
प्रश्न
Use Lewis symbols to show electron transfer between the following atoms to form cations and anions:
Ca and O
Advertisements
उत्तर १
Ca and O:
The electronic configurations of Ca and O are as follows:
Ca: 2, 8, 8, 2
O: 2, 6
Oxygen requires two electrons more to complete its octet, whereas calcium has two electrons more than the nearest noble gas i.e., Argon. Hence, the electron transfer takes place as:
उत्तर २
APPEARS IN
संबंधित प्रश्न
Write Lewis symbols for the following atoms and ions: S and S2–.
Write Lewis symbols for the following atoms and ions: Al and Al3+.
Write Lewis symbols for the following atoms and ions H and H–.
Use Lewis symbols to show electron transfer between the following atoms to form cations and anions:-
K and S
Use Lewis symbols to show electron transfer between the following atoms to form cations and anions:
Al and N
Select and write the most appropriate alternatives from the given choices.
When the following bond types are listed in decreasing order of strength (strongest first). Which is the correct order?
Draw Lewis electron dot structure of HF
Draw Lewis electron dot structure of C2H6
Draw Lewis electron dot structure of CF3Cl
Explain in brief with one example of coordinate bond
Answer in one sentence:
Covalent bond is directional in nature. Justify.
In which of the following, the central atom does NOT have lone pair(s) of electrons?
What is the formal charge on hydrogen atom in water molecule?
Match the items given in Column I with examples given in Column II.
| Column I | Column II |
| (i) Hydrogen bond | (a) \[\ce{C}\] |
| (ii) Resonance | (b) \[\ce{LiF}\] |
| (iii) Ionic solid | (c) \[\ce{H2}\] |
| (iv) Covalent solid | (d) \[\ce{HF}\] |
| (e) \[\ce{O3}\] |
Assertion (A): Sodium chloride formed by the action of chlorine gas on sodium metal is a stable compound.
Reason (R): This is because sodium and chloride ions acquire octet in sodium chloride formation.
What is the formal charge present on the oxygen atom (numbered 1) in the Lewis structure of CO2?
\[\ce{^\bullet_\bullet {\ce{O}} ≡ C - \overset{\bullet\bullet}{\underset{\bullet\bullet}{O^\bullet_\bullet}}}\]
