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प्रश्न
Use a method of your own choice to find the H.C.F. of 24, 36, 60, and 132.
बेरीज
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उत्तर
Factor of 24 = F24 = 2 x 2 x 2 x 3
Factor of 36 = F36 = 2 x 2 x 3 x 3
Factor of 60 = F60 = 2 x 2 x 3 x 5
and Factor of 132 = F132 = 2 x 2 x 3 x 11
Now the common factors of 24, 36, 60 and 132 = 2, 2 and 3
H.C.F. = 2 x 2 x 3 = 12
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