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Two sources of sound are separated by a distance of 4 m. They both emit sound with the same amplitude and frequency (330 Hz), but they are 180° out of phase.

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प्रश्न

Two sources of sound are separated by a distance of 4 m. They both emit sound with the same amplitude and frequency (330 Hz), but they are 180° out of phase. At what points between the two sources, will the sound intensity be maximum?

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उत्तर

∴ λ = `"v"/"n"=330/330` = 1 m

The path difference between two sources of sound is zero when they are directly in the centre of each other. However, because the waves are 180° out of phase, two maxima on either side should be at a distance of `λ/4` from the centre. Other maxima will be located each `λ/2` along the way.

As a result, the maximum sound intensity will be ± 0.25, ± 0.75, ± 1.25, and ± 1.75 m from the point at the centre.

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Speed of Wave Motion
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 6: Superposition of Waves - Exercises [पृष्ठ १५७]

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बालभारती Physics [English] Standard 12 Maharashtra State Board
पाठ 6 Superposition of Waves
Exercises | Q 12 | पृष्ठ १५७

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