Question

Two point masses, each equal to 1 kg, attract 9 one another with a force of 10^–9 kg-wt. The distance between the point masses is nearly [G = 6.6 × 10^–11 MKS units]

पर्याय

• 80 cm

• 8 cm

• 0.8 cm

• 0.08 cm

Answer 1

8 cm

Explanation:

F = 10^–9 kg-wt = 10^–9 × 9.8 N,

F = `(GM_1M_2)/R^2`

∴ R² = `(GM_1M_2)/F = (6.67 xx 10^-11 xx 1 xx 1)/(10^-9 xx 9.8) = 0.68 xx 10^-2` m

∴ R ≈ 0.08 m = 8 cm