Question

Two parallel plates have a potential difference of 10 V between them. If the plates are 0.5 mm apart, what will be the strength of electric charge.

Answer 1

Given: V = 10 V, d = 0.5 mm = 0.5 × 10⁻³ m

To find: Strength of electric field (E) = ?

Formula: E = `V/d`

Calculation: From the formula,

E = `10/(0.5 xx 10^-3`

= 20 × 10³ V/m

∴ The strength of the electric field will be 20 × 10³ V/m.