Advertisements
Advertisements
प्रश्न
Two farmers Thilagan and Kausigan cultivates three varieties of grains namely rice, wheat and ragi. If the sale (in ₹) of three varieties of grains by both the farmers in the month of April is given by the matrix.
`{:("April sale in" ₹)/("rice" "wheat" "ragi"):}`
A = `[(500, 1000, 1500),(2500, 1500, 500)]"Thilagan"/"Kausigan"`
and the May month sale (in ₹) is exactly twice as that of the April month sale for each variety.
What is the average sales for the months of April and May
Advertisements
उत्तर
Let A represent the sale on April
A = `[(500, 1000, 1500),(2500, 1500, 500)]`
Let B represent the sale on May
B = `2[(500, 1000, 1500),(2500, 1500, 500)]`
= `[(1000, 2000, 3000),(5000, 3000, 1000)]`
Average sale of the month April and May
= `1/2["A" + "B"]`
= `1/2{[(500, 1000, 1500),(2500, 1500, 500)] + [(1000, 2000, 3000),(5000, 3000, 1000)]}`
= `1/2[(1500, 3000, 4500),(7500, 4500, 1500)]`
= `[(750, 1500, 2250),(3750, 2250, 750)]`
APPEARS IN
संबंधित प्रश्न
Reduce the following rational expression to its lowest form
`(x^2 - 11x + 18)/(x^2 - 4x + 4)`
Find the excluded values, of the following expression
`"t"/("t"^2 - 5"t" + 6)`
Find the excluded values, of the following expression
`(x^2 + 6x + 8)/(x^2 + x - 2)`
Simplify `("b"^2 + 3"b" - 28)/("b"^2 + 4"b" + 4) ÷ ("b"^2 - 49)/("b"^2 - 5"b" - 14)`
Simplify `(x^3)/(x - y) + (y^3)/(y - x)`
If A = `x/(x + 1)` B = `1/(x + 1)` prove that `(("A" + "B")^2 + ("A" - "B")^2)/("A" + "B") = (2(x^2 + 1))/(x(x + 1)^2`
Solve `1/3` (x + y – 5) = y – z = 2x – 11 = 9 – (x + 2z)
One hundred and fifty students are admitted to a school. They are distributed over three sections A, B and C. If 6 students are shifted from section A to section C, the sections will have equal number of students. If 4 times of students of section C exceeds the number of students of section A by the number of students in section B, find the number of students in the three sections
Reduce the given Rational expression to its lowest form
`(x^(3"a") - 8)/(x^(2"a") + 2x^"a" + 4)`
Simplify `(1/("p") + 1/("q" + "r"))/(1/"p" - 1/("q" + "r")) xx [1 + ("q"^2 + "r"^2 - "p"^2)/(2"qr")]`
