Question

Two dice are thrown simultaneously 500 times. Each time the sum of two numbers appearing on their tops is noted and recorded as given in the following table:

Sum	Frequency
2	14
3	30
4	42
5	55
6	72
7	75
8	70
9	53
10	46
11	28
12	15

If the dice are thrown once more, what is the probability of getting a sum less than or equal to 5?

Answer 1

Total number of times, when two dice are thrown simultaneously, n(S) = 500

Number of times of getting a sum less than or equal to 5,

n(E₂) = 55 + 42 + 30 + 14 = 141

∴ Probability of getting a sum less than or equal to 5 = `(n(E_2))/(n(S)) = 141/500` = 0.282

Hence, the probability of getting a sum less than or equal to 5 is 0.282