Advertisements
Advertisements
प्रश्न
Two 10 cm long, straight wires, each carrying a current of 5A are kept parallel to each other. If each wire experienced a force of 10-5 N, then separation between the wires is ______cm.
पर्याय
5
6
7
8
MCQ
रिकाम्या जागा भरा
Advertisements
उत्तर
Two 10 cm long, straight wires, each carrying a current of 5A are kept parallel to each other. If each wire experienced a force of 10-5 N, then separation between the wires is 5 cm.
Explanation:
We have
`"F"/"l"=mu_0/(2pi)("i"_1"i"_2)/"r"`
⇒ r = `mu_0/(2pi)"i"_1"i"_2xx"l"/"F"`
⇒ r = 2 × 10-7 × 25 × `0.1/10^-5`
= 50 × 10-7 × 104
= 50 × 10-3 m
= 5 cm
shaalaa.com
Force and Torque on Current Carrying Conductor
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
