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प्रश्न
पर्याय
2Ω
4Ω
8Ω
16Ω
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उत्तर
4Ω
Explanation:
Given:
Resistance in the right gap of the meter bridge, R = 4Ω
The null point is at l = 20 cm from the left end.
The total length of the wire = 100 cm.
The gold bangle is connected across the left gap between two diametrically opposite points.
The equivalent resistance between the two opposite points is:
`R_(eq) = "R/2 × R/2"/"R/2 + R/2" = R/4`
Apply the Meter Bridge Principle
`R_"left"/R_"right" = l/(100-l)`
Rleft = Req = `R/4`
Rright = 4Ω
l = 20 cm
`"R/4"/4 = 20/80`
`R/15 = 1/4`
Multiply both sides by 16:
R = 4Ω
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