Question

The width of each of five continuous classes in a frequency distribution is 5 and the lower class-limit of the lowest class is 10. The upper class-limit of the highest class is ______.

पर्याय

• 15

• 25

• 35

• 40

Answer 1

The width of each of five continuous classes in a frequency distribution is 5 and the lower class-limit of the lowest class is 10. The upper class-limit of the highest class is 35.

Explanation:

Let x and y be the upper and lower class limit of frequency distribution.

Given, width of the class = 5

⇒ x – y = 5  ...(i)

Also, given lower class (y) = 10

On putting y = 10 in equation (i), we get

x – 10 = 5

⇒ x = 15

So, the upper-class limit of the lowest class is 15.

Hence, the upper-class limit of the highest class

= (Number of continuous classes × Class width + Lower class limit of the lowest class)

= 5 × 5 + 10

= 25 + 10 

= 35

Hence, the upper-class limit of the highest class is 35.

Answer 2

The width of each of five continuous classes in a frequency distribution is 5 and the lower class-limit of the lowest class is 10. The upper class-limit of the highest class is 35.

Explanation:

After finding the upper-class limit of the lowest class, the five continuous classes in a frequency distribution with width 5 are 10 – 15, 15 – 20, 20 – 25, 25 – 30 and 30 – 35.

Thus, the highest class is 30 – 35,

Hence, the upper limit of this class is 35.