Question

The wavelengths of a certain blue light in air and in glass are 480 nm and 320 nm, respectively. Find the Brewster angle for this blue light incident on the glass.

Answer 1

Data: λ_a = 480 nm, λ_g = 320 nm

n = `(λ_a)/(λ_g)` and n = tan θ_B

∴ tan θ_B = `(λ_a)/(λ_g)`

= `480/320`

= 1.5

∴ θ_B = tan−1

= 1.5

= 56°19

This is the required Brewster angle.