Question

The value of `sin θ/(cos(90^circ - θ)) + cos 43^circ/sin 47^circ` is ______.

Answer 1

The value of `sin θ/(cos(90^circ - θ)) + cos 43^circ/sin 47^circ` is 2.

Explanation:

`sin θ/(cos(90^circ - θ)) + cos 43^circ/sin 47^circ`

= `sin θ/(cos(90^circ - θ)) + (cos(90^circ - 47^circ))/sin 47^circ`

= `sin θ/sin θ + sin 47^circ/sin 47^circ`   ...[∵ cos (90° – A) = sin A]

= 1 + 1

= 2