Question

The value of series limit in the case of paschen series is ______.

पर्याय

• 1875 nm

• 122 nm

• 822 nm

• tending to zero

Answer 1

The value of series limit in the case of paschen series is 822 nm.

Explanation:

For series limit of Paschen series, transition from n₁ = 3 to n₂ = ∞

`1/lambda = R(1/n_1^2 - 1/n_2^2)`

= `R(1/3^2 - 1/∞^2)`

`1/lambda = R/9`

⇒ `lambda = 9/R = 9 xx 912` Å

= `82.8 xx 10^-9`

= 822 nm