Advertisements
Advertisements
प्रश्न
The value of cos(-480°) is:
पर्याय
`sqrt3`
`- sqrt3/2`
`1/2`
`(-1)/2`
MCQ
Advertisements
उत्तर
`(-1)/2`
Explanation:
cos(-480°) = cos 480° [∵ cos(-θ) = cos θ]
= cos(360° + 120°)
= cos 120°
= cos(180° – 60°)
= -cos 60°
= `(-1)/2`
shaalaa.com
Trigonometric Ratios of Compound Angles
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
Find the value of the following:
cosec 15º
Find the value of the following:
sin 76° cos 16° – cos 76° sin 16°
If A + B = 45°, prove that (1 + tan A) (1 + tan B) = 2 and hence deduce the value of tan 22`1/2`.
Prove that:
sin(A + 60°) + sin(A – 60°) = sin A.
If tan A – tan B = x and cot B – cot A = y prove that cot(A – B) = `1/x + 1/y`.
Prove that cot 4x (sin 5x + sin 3x) = cot x(sin 5x - sin 3x).
Find the value of sin 75°.
Show that `cos^-1 (12/13) + sin^-1 (3/5) = sin^-1 (56/65)`
The value of sin (-420°)
If sin A + cos A = 1 then sin 2A is equal to:
