Advertisements
Advertisements
प्रश्न
The value of 1 – 2 sin2 45° is:
पर्याय
1
`1/2`
`1/4`
0
MCQ
Advertisements
उत्तर
0
Explanation:
1 – 2 sin2 45°
= cos(2 × 45°) [∵ cos 2A = 1 – 2 sin2 A]
= cos 90°
= 0
shaalaa.com
Trigonometric Ratios of Compound Angles
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
Find the value of the following:
sin (-105°)
If sin A = `3/5`, 0 < A < `pi/2` and cos B = `(-12)/13`, π < B < `(3pi)/2`, find the values of the following:
- cos(A + B)
- sin(A – B)
- tan(A – B)
Prove that:
tan 4A tan 3A tan A + tan 3A + tan A – tan 4A = 0
If sin A = `3/5`, find the values of cos 3A and tan 3A.
Prove that `(sin ("B - C"))/(cos "B" cos "C") + (sin ("C - A"))/(cos "C" cos "A") + (sin ("A - B"))/(cos "A" cos "B")` = 0
Find the value of tan `pi/8`.
If cos (α + β) = `4/5` and sin (α - β) = `5/13` where (α + β) and (α - β) are acute, then find tan 2α.
The value of sin 15° is:
The value of sec A sin(270° + A) is:
The value of cos2 45° – sin2 45° is:
