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प्रश्न
The sum of the squares deviations for 10 observations taken from their mean 50 is 250. The coefficient of variation is
पर्याय
10 %
40 %
50 %
none of these
MCQ
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उत्तर
10 %
\[\text{ We have } : \]
\[X = 50, n = 10 \]
\[ \sum^{10}_{i = 1} \left( x_i - X \right)^2 = 250\]
\[ \therefore SD = \sqrt{\text{ Variance} of X} \]
\[ = \sqrt{\frac{\sum^{10}_{i = 1} \left( x_i - X \right)^2}{n}} \]
\[ = \sqrt{\frac{250}{10}}\]
\[ = 5\]
Using \[CV = \frac{\sigma}{X} \times 100\]
\[\Rightarrow CV = \frac{5}{50} \times 100 \]
\[ = 10\] %
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