Advertisements
Advertisements
प्रश्न
The sum of the squares of two numbers is 13 and their product is 6. Find:
(i) the sum of the two numbers.
(ii) the difference between them.
Advertisements
उत्तर
Let x and y be the two numbers, then,
x2 + y2 = 13 and xy = 6
(i) (x + y)2 = x2 + y2 + 2xy
= 13 + 2×6
= 13 + 12
= 25
∴ x + y = ± `sqrt25` = ±5
(ii) (x − y)2 = x2 + y2 − 2xy
= 13 − 12
= 1
∴ x − y = ±1
APPEARS IN
संबंधित प्रश्न
If a – b = 6 and ab = 16, find a2 + b2
If a2 + b2 = 29 and ab = 10, find : a + b
If a2 + b2= 10 and ab = 3; find : a + b
Find : a + b + c, if a2 + b2 + c2 = 83 and ab + bc + ca = 71.
If a + b = 6 and ab = 8, find: a3 + b3.
If a – b = 3 and ab = 10, find : a3 – b3.
Find:
`a^3-1/a^3`, if `a -1/a = 4`.
If `2"x"-1/(2"x")=4`, find : `4"x"^2+1/(4"x"^2)`
If a + b + c = 11 and a2 + b2 + c2 = 81, find : ab + bc + ca.
If 5x – 4y = 7 and xy = 8, find : 125x3 – 64y3.
