मराठी

The sum of first n odd natural numbers is ______. - Mathematics

Advertisements
Advertisements

प्रश्न

The sum of first n odd natural numbers is ______.

पर्याय

  •  2n - 1

  •  2n + 1

  • n2

  • n2 - 1

MCQ
रिकाम्या जागा भरा
Advertisements

उत्तर

The sum of first n odd natural numbers is n2.

Explanation:-

In this problem, we need to find the sum of first n odd natural numbers.

So, we know that the first odd natural number is 1. Also, all the odd terms will form an A.P. with the common difference of 2.

So here,

First term (a) = 1

Common difference (d) = 2

So, let us take the number of terms as n

Now, as we know,

`S_n = n/2 [ 2a + ( n- 1) d]`

So, for n terms,

`S_n = n/2 [ 2(1) + ( n- 1) 2 ]`

`=n/2[2+2n-2]`

`=n/2(2n)`

= n2

Therefore, the sum of first n odd natural numbers is `S_n = n^2`.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 5: Arithmetic Progression - Exercise 5.8 [पृष्ठ ५९]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 10
पाठ 5 Arithmetic Progression
Exercise 5.8 | Q 28 | पृष्ठ ५९

संबंधित प्रश्‍न

How many terms of the A.P. 18, 16, 14, .... be taken so that their sum is zero?


In an AP given a = 8, an = 62, Sn = 210, find n and d.


If the nth term of the A.P. 9, 7, 5, ... is same as the nth term of the A.P. 15, 12, 9, ... find n.


Find the sum of the following arithmetic progressions:

41, 36, 31, ... to 12 terms


In an A.P., if the first term is 22, the common difference is −4 and the sum to n terms is 64,  find n.


Determine k so that (3k -2), (4k – 6) and (k +2) are three consecutive terms of an AP.


The sum of the first n terms of an AP is given by  `s_n = ( 3n^2 - n) ` Find its

(i) nth term,
(ii) first term and
(iii) common difference.

 


Find the 25th term of the AP \[- 5, \frac{- 5}{2}, 0, \frac{5}{2}, . . .\]

 


Find the first term and common difference for  the A.P.

0.6, 0.9, 1.2,1.5,...


The first term of an A. P. is 5 and the common difference is 4. Complete the following activity and find the sum of the first 12 terms of the A. P.

a = 5, d = 4, s12 = ?
`s_n = n/2 [ square ]`
`s_12 = 12/2 [10 +square]`
         `= 6 × square  `
         ` =square`


The sum of first seven terms of an A.P. is 182. If its 4th and the 17th terms are in the ratio 1 : 5, find the A.P.


A man is employed to count Rs 10710. He counts at the rate of Rs 180 per minute for half an hour. After this he counts at the rate of Rs 3 less every minute than the preceding minute. Find the time taken by him to count the entire amount.


Write the nth term of an A.P. the sum of whose n terms is Sn.

 

If the first term of an A.P. is 2 and common difference is 4, then the sum of its 40 terms is 


How many terms of the A.P. 25, 22, 19, … are needed to give the sum 116 ? Also find the last term.


Find second and third terms of an A.P. whose first term is – 2 and the common difference is – 2.


In an AP, if Sn = n(4n + 1), find the AP.


Find the sum of first 17 terms of an AP whose 4th and 9th terms are –15 and –30 respectively.


Find the sum of all the 11 terms of an A.P. whose middle most term is 30.


Find the sum of all odd numbers between 351 and 373.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×