Advertisements
Advertisements
प्रश्न
The sum of diameters of two circles is 112cm and the sum of their areas is 5236cm2. Find the radii of the two circles.
Advertisements
उत्तर
Let one of two circles touching externally have a radius of R and the other have radius r
Given 2R + 2r
= 112cm R + r
= 56cm.
So, R = 56 - r
The Area of a Circle with radius r = πr2
The Area of a Circle with radius R = πR2
Sum of the areas of the two circles
= πr2 + πR2
= π(r2 + R2)
= 5236
⇒ r2 + R2 = 1666
⇒ r2 + 56
⇒ 2r2 - 112r + 1470 = 0
⇒ r2 - 56r + 735 = 0
⇒ r2 - 35r - 21r + 735 = 0
⇒ r(r - 35) - 21(r - 35) = 0
⇒ (r - 35)(r - 21) = 0
⇒ r = 35, 21
So, one of the two circles touching externally has a radius of 35cm and the other has radius 21cm.
APPEARS IN
संबंधित प्रश्न
One side of a rectangle is 12 cm long and its diagonal measure 37 cm. Find the other side and the area of the rectangle.
Find the perimeter and area of the quadrilateral ABCD in which AB = 17 cm, AD = 9 cm, CD = 12 cm, ∠ACB=90° and AC = 15 cm.
In the the following figure, PSR, RTQ and PAQ are three semicircles of diameter 10 cm, 3 cm and 7 cm respectively. Find the perimeter of shaded region.

Write the formula for the area of a sector of angle \[\theta\] (in degrees) of a circle of radius r.
If the sum of the areas of two circles with radii r1 and r2 is equal to the area of a circle of radius r, then \[r_1^2 + r_2^2\]
The area of a circular path of uniform width h surrounding a circular region of radius r is
In the given figure, a square OABC has been inscribed in the quadrant OPBQ. If OA = 20 cm, then the area of the shaded region is

A steel wire, when bent in the form of a square, encloses an area of 121 cm2. The same wire is bent in the form of a circle. Find area the circle.
Find the area of a flat circular ring formed by two concentric circles (circles with the same centre) whose radii are 9 cm and 5 cm.
Find the area enclosed between two concentric circles, If their radii are 6cm and 13cm respectively.
