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The sum of a number and its reciprocal is 17/4. Find the number.
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Let the number be ‘x’
According to the given hypothesis
`x+1/x=17/4`
`rArr(x^2+1)/x=17/4`
⇒ 4(ЁЭСе2 + 1) = 17ЁЭСе
⇒ 4ЁЭСе2 - 17ЁЭСе + 4 = 0
⇒ 4ЁЭСе2 - 16ЁЭСе - ЁЭСе + 4 = 0
⇒ 4ЁЭСе(ЁЭСе - 4) - 1(ЁЭСе - 4) = 0
⇒ ЁЭСе =1/4 ЁЭСЬЁЭСЯ ЁЭСе = 4
∴ The value of ЁЭСе = 4
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