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प्रश्न
The sum and product of zeroes of a quadratic polynomial p(x) are `(-1)/3 and 2` respectively. The polynomial p(x) is ______.
पर्याय
3x2 − x + 6
`x^2 + 1/3 x - 2`
3x2 − x + 2
−3x2 − x − 6
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उत्तर
The sum and product of zeroes of a quadratic polynomial p(x) are `(-1)/3 and 2` respectively. The polynomial p(x) is 3x2 + x + 6.
Explanation:
Let sum of quadratic polynomial is α + β = `(-1)/3`
Product of the quadratic polynomial is (αβ) = 2
The required polynomial g(x) is given by
p(x) = k[x2 − Sx + P]
p(x) = k[x2 − (α + β) x + (αβ)]
p(x) = `k[x^2 - (-1/3)x + 2]`
= `k[x^2 + 1/3 x + 2]`
To eliminate the fraction, we can choose k = 3
p(x) = `3(x^2 + 1/3 x + 2)`
= 3x2 + 3x + 6
Wait, let’s re-examine the options and the signs. If we take k = −3.
p(x) = `-3(x^2 + 1/3 x + 2)`
= −3x2 − x − 6
