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प्रश्न
The straight lines 3x − 5y = 7 and 4x + ay + 9 = 0 are perpendicular to one another. The value of a is ______.
पर्याय
`-5/12`
`5/12`
`12/5`
`-12/5`
MCQ
रिकाम्या जागा भरा
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उत्तर
The straight lines 3x − 5y = 7 and 4x + ay + 9 = 0 are perpendicular to one another. The value of a is `ulbb(12/5)`.
Explanation:
For two lines a1x + b1y = c1 = and a2x + b2y = c2 to be perpendicular, the product of their x coefficients plus the product of their y coefficients must be zero:
(a1 × a2) + (b1 × b2) = 0
Identify coefficients:
⇒ Line 1 (3x − 5y = 7): a1 = 3, b1 = −5
⇒ Line 2 (4x + ay + 9 = 0): a2 = 4, b2 = a
Plug into formula:
3(4) + (−5)(a) = 0
12 − 5a = 0
5a = 12
∴ `a = 12/5`
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