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प्रश्न
The standard heat of formation, in kcal/mol of Ba2+ is:
[Given: Standard heat of formation of \[\ce{SO^{2-}4}\] ion (aq) = −216 kcal/mol, standard heat of crystallisation of BaSO4(s) = −4.5 kcal/mol, standard heat of formation of BaSO4(s) = −349 kcal/mol]
पर्याय
−128.5
−133.0
+133.0
+220.5
MCQ
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उत्तर
−128.5
Explanation:
\[\ce{Ba^{2+}_{ (aq)} + SO^{2-}_{4(aq)} -> BaSO4(s)}\]
ΔHr = ∑ΔHf(Products) − ∑ΔHf(Reactants)
−4.5 = [ΔHf(BaSO4)] − [ΔHf(Ba2+) + ΔHf\[\ce{(SO^{2-}4)}\]]
−4.5 = [−349] − [ΔHf(Ba2+) + (−216)]
−4.5 = −349 − ΔHf(Ba2+) + 216
−4.5 = −133 − ΔHf(Ba2+)
ΔHf(Ba2+) = −133 + 4.5
ΔHf(Ba2+) = −128.5 kcal mol−1
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