Question

The speed of light in diamond of refractive index 2.5 is:

[v_Air = 3 × 10⁸ ms⁻¹]

पर्याय

• 1.25 × 10⁸ ms⁻¹

• 1.20 × 10⁸ ms⁻¹

• 1.18 × 10⁸ ms⁻¹

• 1.22 × 10⁸ ms⁻¹

Answer 1

1.20 × 10⁸ ms⁻¹

Explanation:

\[ \text{Using } \mu = \frac{v_{\text{Air}}}{v_{\text{diamond}}}\]

\[ \text{we get } v_{\text{diamond}} = \frac{3 \times 10^{8}}{2.5} \]

= 1.20 × 10⁸ ms⁻¹