Question

The slope of the line obtained on plotting \[\text{log}_{10}\frac{x}{m}\] against log₁₀ P is equal to ______.

Answer 1

The slope of the line obtained on plotting \[\text{log}_{10}\frac{x}{m}\] against log₁₀ P is equal to `\underlinebb(1/n)`.

Explanation:

According to the Freundlich adsorption isotherm,

`x/m = kP^(1//n)`,

where `(x/m)` is the amount adsorbed per unit mass of adsorbent, (P) is the pressure, and (k) and (n) are constants.

Taking the logarithm base 10 of both sides gives:

\[\text{log}_{10}\frac{x}{m} = \frac{1}{n} \text{log}_{10}P + \text{log}_{10} k\]

Thus, when \[\text{log}_{10}\frac{x}{m}\] is plotted against log₁₀ P, the slope of the resulting line is `1/n`.