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प्रश्न
The slope of the line obtained on plotting log10[A] vs t for a first order reaction is ______.
रिकाम्या जागा भरा
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उत्तर
The slope of the line obtained on plotting log10[A] vs t for a first order reaction is `bbunderline(- k/2.303)`.
Explanation:
The integrated rate law for a first-order reaction is:
log10[A] = `log_10[A] - k/2.303 t`
This equation is in the form of a straight line:
y = mx + c
where:
y = log10[A],
x = t,
slope (m) = `− k/2.303`
So, the slope is negative and equals `− k/2.303`
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