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प्रश्न
The short and long hands of a clock are 4 cm and 6 cm long respectively. Find the sum of distances travelled by their tips in 2 days.
बेरीज
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उत्तर
Given:
Short hand (hour hand) length = 4 cm
Long hand (minute hand) length = 6 cm
Time = 2 days = 48 hours
Distance travelled by hour hand
Length = radius = 4 cm
Circumference =
2πr = 2π(4) = 8π cm
Hour hand completes 1 rotation in 12 hours.
`48/12`
= 4 rotations
4 × 8π = 32π cm
Distance travelled by minute hand
Length = 6 cm
2πr = 2π(6)
= 12π cm
Minute hand completes 1 rotation every hour.
48 rotations
48 × 12π
= 576π cm
Total distance travelled by both hands
32π + 576π
= 608π cm
If π = 3.14:
608 × 3.14
= 1908 cm
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