मराठी

The resistance of a decinormal solution of a salt occupying a volume between two platinum electrodes 1.80 cm apart and 5.4 cm2 in area was found to be 32 ohms. Calculate the specific and equivalent - Chemistry (Theory)

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प्रश्न

The resistance of a decinormal solution of a salt occupying a volume between two platinum electrodes 1.80 cm apart and 5.4 cm2 in area was found to be 32 ohms.

Calculate the specific and equivalent conductances of the solution.

संख्यात्मक
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उत्तर

Given:

Distance between electrodes, l = 1.80 cm

Area of electrodes A = 5.4 cm2

Resistance R = 32 Ω

Concentration = decinormal = 0.1 N

`"Cell constant" = l/A`

= `1.80/5.4`

= 0.333 cm−1

The specific conductance, κ:

`kappa = "Cell constant" xx 1/R`

= `0.333 xx 1/32`

= 0.0104 ohm−1 cm−1

The equivalent conductance, Λeq:

`Lambda_"eq" = (kappa xx 1000)/N`

= `(0.0104 xx 1000)/0.1`

= 104 ohm−1 cm2 eq−1

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पाठ 3: Electrochemistry - REVIEW EXERCISES [पृष्ठ १६५]

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नूतन Chemistry Part 1 and 2 [English] Class 12 ISC
पाठ 3 Electrochemistry
REVIEW EXERCISES | Q 3.46 | पृष्ठ १६५
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