Question

The rate law for the reaction

\[\ce{RCl + NaOH_{(aq)} -> ROH + NaCl}\] 

is given by, Rate = k [RCl]. The rate of reaction will be ______.

पर्याय

• unaffected by increasing the temperature of the reaction.

• doubled on doubling the concentration of NaOH.

• halved on reducing the concentration of NaOH to one half.

• halved on reducing the concentration of RCl to one half.

Answer 1

The rate law for the reaction

\[\ce{RCl + NaOH_{(aq)} -> ROH + NaCl}\] 

is given by, Rate = k [RCl]. The rate of reaction will be halved on reducing the concentration of RCl to one half.

Explanation:

According to the rate law Rate = k [RCl], the reaction is first-order in RCl and independent of NaOH. Therefore, halving the concentration of RCl will halve the reaction rate. Changes in [NaOH] do not affect the rate.