Advertisements
Advertisements
प्रश्न
The radius of a circle is 21 cm. Find the circumference (Take π = `3 1/7`).
Advertisements
उत्तर
Given, radius (r) = 21 cm and π =`22/7`
Circumference of the circle = 2πr
= `2xx22/7xx21` cm
= 2 × 22 × 3 cm
= 132 cm
APPEARS IN
संबंधित प्रश्न
In Fig. 4, ABCD is a square of side 14 cm. Semi-circles are drawn with each side of square as diameter. Find the area of the shaded region.
(use `pi=22/7`)

An arc of a circle is of length 5π cm and the sector it bounds has an area of 20 π cm2. Find the radius of the circle.
The circumference of a circle exceeds diameter by 16.8 cm. Find the circumference of
circle.
The perimeter of a rhombus is 60 cm. If one of its diagonals is 18 cm long, find
(i) the length of the other diagonal, and
(ii) the area of the rhombus.
In a circle of radius 10.5 cm, the minor arc is one-fifth of the major arc. Find the area of the sector corresponding to the major arc.
The inside perimeter of a running track shown in the figure is 400 m. The length of each of the straight portions is 90 m, and the ends are semicircles. If the track is 14 m wide everywhere, find the area of the track. Also, find the length of the outer boundary of the track.

OACB is a quadrant of a circle with centre O and its radius is 3.5 cm. If OD = 2 cm. find the area of
- the quadrant OACB
- the shaded region.
[Take `π = 22/7`.]

A 7 m road surrounds a circular garden whose area is 5544 m2. Find the area of the road and the cost of tarring it at the rate of Rs.150 per sq m.
A canvas tent is in the shape of a cylinder surmounted by a conical roof. The common diameter of the cone and the cylinder is 14 m. The height of the cylindrical part is 8 m and the height of the conical roof is 4 m. Find the area of the canvas used to make the tent.
A lawn is in the shape of a semi-circle of diameter 42 m. The lawn is surrounded by a flower bed of width 7 m all around. Find the area of the flower bed in m2 .
