Advertisements
Advertisements
प्रश्न
The population of a town decreased by 12% during 1998 and then increased by 8% during 1999. Find the population of the town, at the beginning of 1998, if at the end of 1999 its population was 2,85,120.
Advertisements
उत्तर
Let the population in the beginning of 1998 = P
The population at the end of 1999 = 2,85,120(A)
r1 = - 12% and r2 = + 8%
∴ A = P`( 1 - r_1/100 )( 1 + r_2/100 )`
⇒ 2,85,120 = P`( 1 - 12/100 )( 1 + 8/100 )`
⇒ 2,85,120 = P`( 22/25 )( 27/25 )`
⇒ P = `[ 2,85,120 xx 25 xx 25 ]/[ 22 xx 27 ]` = 3,00,000.
APPEARS IN
संबंधित प्रश्न
The value of an article decreases for two years at the rate of 10% per year and then in the third year it increases by 10%. Find the original value of the article, if its value at the end of 3 years is Rs. 40,095.
According to a census taken towards the end of the year 2009, the population of a rural town was found to be 64,000. The census authority also found that the population of this particular town had a growth of 5% per annum. In how many years after 2009 did the population of this town reach 74,088 ?
The difference between compound interest for a year payable half-yearly and simple interest on a certain sum of money lent out at 10% for a year is Rs. 15. Find the sum of money lent out.
Find the amount and the compound interest payable annually on:
Rs.16000 for 2 years at 15% and 12% for the successive years.
Find the amount and compound interest on Rs.7500 for 1`(1)/(2)` years at 8%, payable semi-annually.
Find the amount and the compound interest on the following:
Rs.8000 for 3years at 10% per annum compounded annually.
Find the amount on Rs 36000 in 2 years 15% p.a. compounded annually.
Calculate the rate percent when Rs 28000 amount to Rs 30870 in 2 years at compounded annually.
In what time will Rs 15625 amount to Rs 17576 at 4% p.a. compound interest?
At what rate percent will Rs.12000 yield Rs.13891.50 as compound interest in 3 years?
