Advertisements
Advertisements
प्रश्न
The perimeter of a semicircular plate is 108 cm. find its area.
Advertisements
उत्तर
The perimeter of a semi-circular plate = 108 cm
⇒ πr + 2r = 108 ...(r is radius of a circle )
⇒ r ( π + 2 ) = 108
⇒ r = ` (108)/( π + 2) = (108)/(22/7 + 2) = (108 xx 7) / (36) = 21 "cm"`
Now, area of a semi-ccircular pleate = `[πr^2]/2 = [22/7 xx 21 xx 21]/2 = 693 "cm"^2`
APPEARS IN
संबंधित प्रश्न
The area of a parallelogram is y cm2 and its height is h cm. The base of another parallelogram is x cm more than the base of the first parallelogram and its area is twice the area of the first. Find, in terms of y, h, and x, the expression for the height of the second parallelogram.
Calculate the area of quadrilateral ABCD in which AB = 32 cm, AD = 24 cm ∠A = 90° and BC = CD = 52 cm.
A wire when bent in the form of a square encloses an area of 484 m2. Find the largest area enclosed by the same wire when bent to from:
- An equilateral triangle.
- A rectangle of length 16 m.
The perimeter of a rhombus is 52 cm. If one diagonal is 24 cm; find:
(i) The length of its other diagonal,
(ii) Its area.
Two adjacent sides of a parallelogram are 24 cm and 18 cm. If the distance between the longer sides is 12 cm; find the distance between the shorter sides.
Two adjacent sides of a parallelogram are 28 cm and 26 cm. If one diagonal of it is 30 cm long; find the area of the parallelogram. Also, find the distance between its shorter sides.
Find the area and the perimeter of a square with diagonal 24 cm. [Take √2 = 1.41 ]
Find the value of k, if the area of a quadrilateral is 28 sq. units, whose vertices are (– 4, – 2), (– 3, k), (3, – 2) and (2, 3)
Find the area of quadrilateral BCEG
When proving that a quadrilateral is a parallelogram by using slopes you must find
