Question

The oxidation states of nitrogen in NO, NO₂, N₂O and \[\ce{NO^-_3}\] are in the order of:

पर्याय

• \[\ce{NO^-_3}\] > NO₂ > NO > N₂O

• NO₂ > \[\ce{NO^-_3}\] > NO > N₂O

• N₂O > NO₂ > NO > \[\ce{NO^-_3}\]

• NO > NO₂ > N₂O > \[\ce{NO^-_3}\]

Answer 1

\[\ce{\mathbf{NO^-_3}}\] > NO₂ > NO > N₂O

Explanation:

To arrange the compounds, we calculate the oxidation state of nitrogen:

In \[\ce{NO^-_3}\]: +5

In NO₂: +4

In NO: +2

In N₂O: +1

Thus, the correct decreasing order is:

\[\ce{NO^-_3}\] (+5) > NO₂ (+4) > NO (+2) > N₂O (+1)