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The oxidation number of an element in a compound is evaluated on the basis of certain rules. Which of the following rules is not correct in this respect? - Chemistry

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प्रश्न

The oxidation number of an element in a compound is evaluated on the basis of certain rules. Which of the following rules is not correct in this respect?

पर्याय

  • The oxidation number of hydrogen is always +1.

  • The algebraic sum of all the oxidation numbers in a compound is zero.

  • An element in the free or the uncombined state bears oxidation number zero.

  • In all its compounds, the oxidation number of fluorine is – 1.

MCQ
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उत्तर

The oxidation number of hydrogen is always +1.

Explanation:

Oxidation number of hydrogen is – 1 in metal hydrides like \[\ce{NaH}\].

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Oxidation Number - Introduction
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 8: Redox Reactions - Multiple Choice Questions (Type - I) [पृष्ठ १०५]

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एनसीईआरटी एक्झांप्लर Chemistry [English] Class 11
पाठ 8 Redox Reactions
Multiple Choice Questions (Type - I) | Q 6 | पृष्ठ १०५

संबंधित प्रश्‍न

Assign oxidation numbers to the underlined element in the following species:

H4P2O7


Assign oxidation numbers to the underlined elements in the following species:

K2MnO4


Assign oxidation numbers to the underlined elements in the following species:

CaO2


Assign oxidation numbers to the underlined elements in the following species:

NaBH4 


What is the oxidation numbers of the underlined elements in the following and how do you rationalise your results?

 Fe3O4


What are the oxidation numbers of the underlined elements in the following and how do you rationalise your results?

CH3CH2OH


Consider the elements: Cs, Ne, I and F

Identify the element that exhibits only negative oxidation state.


Consider the elements: Cs, Ne, I and F

Identify the element that exhibits both positive and negative oxidation states.


The exhibition of various oxidation states by an element is also related to the outer orbital electronic configuration of its atom. Atom(s) having which of the following outermost electronic configurations will exhibit more than one oxidation state in its compounds.

(i) 3s1

(ii) 3d14s2

(iii) 3d24s2

(iv) 3s23p3 


Nitric acid is an oxidising agent and reacts with \[\ce{PbO}\] but it does not react with \[\ce{PbO2}\]. Explain why?


Calculate the oxidation number of phosphorus in the following species.

\[\ce{PO^{3-}4}\]


Calculate the oxidation number of sulphur atom in the following compounds:

\[\ce{Na2S2O3}\]


Match Column I with Column II for the oxidation states of the central atoms.

Column I Column II
(i) \[\ce{Cr2O^{2-}7}\] (a) + 3
(ii) \[\ce{MnO^{-}4}\] (b) + 4
(iii) \[\ce{VO^{-}3}\] (c) + 5
(iv) \[\ce{FeF^{3-}6}\] (d) + 6
  (e) + 7

Match Column I with Column II for the oxidation states of the central atoms.

  Column I Column II
(i) Ions having positive charge (a) +7
(ii) The sum of oxidation number
of all atoms in a neutral molecule
(b) –1
(iii) Oxidation number of hydrogen ion \[\ce{(H+)}\] (c) +1
(iv) Oxidation number of fluorine in \[\ce{NaF}\] (d) 0
(v) Ions having negative charge (e) Cation
    (f) Anion

The oxidation number of U in \[\ce{UO2(NO3)2}\] is ______. 


The oxidation number and covalency of sulphur in sulphur molecules (Sg) are:


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