Question

The osmotic pressure exerted by a solution prepared by dissolving 2.0 g of protein of molar mass 60 kg mol⁻¹ in 200 mL of water at 27°C is ______ Pa.

(Use R = 0.083 L bar mol⁻¹ K⁻¹)

पर्याय

• 415

• 812

• 81.2

• 0.812

Answer 1

The osmotic pressure exerted by a solution prepared by dissolving 2.0 g of protein of molar mass 60 kg mol⁻¹ in 200 mL of water at 27°C is 415 Pa.

Explanation:

π = iCRT ...`("n"/"v" = "weight"/("Molar mass" xx "volume" (1  "kg" = 1000  "g")))`

= `(1 xx 2)/(60000 xx 0.2) xx 0.083 xx 300`

= 0.00415 bar .....(∵ 1 bar = 10⁵ pa)

= 0.00415 × 10⁵ Pa

= 415 Pa