Advertisements
Advertisements
प्रश्न
The number x is 2 more than the number y. If the sum of the squares of x and y is 34, then find the product of x and y.
Advertisements
उत्तर
Given x is 2 more than y, so x = y + 2
Sum of squares of x and y is 34, so x2 + y2 = 34.
Replace x = y + 2 in the above equation and solve for y.
We get (y + 2)2 + y2 = 34
2y2 + 4y - 30 = 0
y2 + 2y - 15 = 0
(y + 5)(y - 3) = 0
So y = -5 or 3
For y = -5, x =-3
For y = 3, x = 5
Product of x and y is 15 in both cases.
APPEARS IN
संबंधित प्रश्न
Evaluate the following product without multiplying directly:
103 × 107
Factorise the following:
8a3 + b3 + 12a2b + 6ab2
Give possible expression for the length and breadth of the following rectangle, in which their area is given:
| Area : 35y2 + 13y – 12 |
Evaluate following using identities:
(a - 0.1) (a + 0.1)
If a2 + b2 + c2 = 16 and ab + bc + ca = 10, find the value of a + b + c.
If `x - 1/x = 3 + 2sqrt2`, find the value of `x^3 - 1/x^3`
Find the following product:
Evaluate: 203 × 197
Find the squares of the following:
3p - 4q2
Simplify:
`(x - 1/x)(x^2 + 1 + 1/x^2)`
